How to Take a Screenshot of a Website in Python with requests
How to Take a Screenshot of a Website in Python with requests You need a screenshot. You're using Python. You probably have requests installed already. No Selenium. No Puppeteer. One POST call. PNG back. The Problem: Selenium Screenshots Are Slow Typical Selenium approach in Python: from selenium import webdriver from selenium.webdriver.chrome.options import Options options = Options () options . add_argument ( ' --headless ' ) driver = webdriver . Chrome ( options = options ) driver . get ( ' https://example.com ' ) driver . save_screenshot ( ' screenshot.png ' ) driver . quit () Issues: Selenium must manage a real browser process Browser startup takes 3-10 seconds per screenshot Requires system Chrome/Firefox installation Memory intensive Flaky timing issues (page not fully loaded, etc.) Can't run in serverless The Solution: PageBolt API + requests One library. One POST call. Done. import requests response = requests . post ( ' https://api.pagebolt.dev/v1/screenshot ' , headers = { '
Continue reading on Dev.to Python
Opens in a new tab
![[Learning notes and hw] getting started with R-cnn: Manually implementing Intersection over Union (IoU)](/_next/image?url=https%3A%2F%2Fmedia2.dev.to%2Fdynamic%2Fimage%2Fwidth%3D800%252Cheight%3D%252Cfit%3Dscale-down%252Cgravity%3Dauto%252Cformat%3Dauto%2Fhttps%253A%252F%252Fdev-to-uploads.s3.amazonaws.com%252Fuploads%252Farticles%252Favit2emoxc0g68e5ltqj.jpg&w=1200&q=75)
